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source/ch_logic.ptx

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</p>
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<p>
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The problem is, as you no doubt know from arguing with friends, not all arguments are <em>good</em> arguments. A bad argument is one in which the conclusion does not follow from the premises, i.e., the conclusion is not a consequence of the premises. Logic is the study of what makes an argument good or bad. In other words, logic aims to determine in which cases a conclusion is, or is not, a consequence of a set of premises.
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The problem is, as you no doubt know from arguing with friends, not all arguments are <em>good</em> arguments. A bad argument is one in which the conclusion does not follow from the premises; i.e., the conclusion is not a consequence of the premises. Logic is the study of what makes an argument good or bad. In other words, logic aims to determine in which cases a conclusion is, or is not, a consequence of a set of premises.
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</p>
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<!-- TODO: revise summary when settled on new structure -->

source/exercises/logic-implications.ptx

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<exercise>
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<statement>
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<p> Write each of the following statements in the form, <q> If <ellipsis />, then <ellipsis />.</q> Careful, some statements may be false (which is alright for the purposes of this question). <ol>
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<p> Write each of the following statements in the form, <q> If <ellipsis />, then <ellipsis />.</q> Careful, some statements may be false (which is fine for the purposes of this question). <ol>
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<li>
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<p> To lose weight, you must exercise. </p>
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</li>

source/exercises/logic-statements.ptx

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</li>
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<li>
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<p> There is prime number that is even. </p>
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<p> There is a prime number that is even. </p>
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</li>
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<li>

source/practice/logic-statements.ptx

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<exercise label="rs-statements-quant-interpretation">
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<statement>
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<p>
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Regardless of your beliefs of how many people can be fooled at various times, what could you conclude if we reinterpret <m>P(x,y)</m> to mean <m>x \lt y</m> and only quantify over the natural numbers (so <m>\forall x</m> means <q>for all natural numbers</q> and <m>\exists x</m> means <q>there exists a natural number</q>)? Select all of the following that apply.
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Regardless of your beliefs of how many people can be fooled at various times, what could you conclude if we reinterpret <m>P(x,y)</m> to mean <m>x \lt y</m> and only quantify over the natural numbers (so <m>\forall x</m> means <q>For all natural numbers,</q> and <m>\exists x</m> means <q>There exists a natural number</q>)? Select all of the following that apply.
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</p>
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</statement>
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<choices>

source/sec_logic-implications.ptx

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<investigation>
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<statement>
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<p>
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Little Timmy's Mom tells him, <q>if you don't eat all your broccoli, then you will not get any ice cream.</q> Of course, Timmy loves his ice cream, so he quickly eats all his broccoli (which actually tastes pretty good).
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Little Timmy's Mom tells him, <q>If you don't eat all your broccoli, then you will not get any ice cream.</q> Of course, Timmy loves his ice cream, so he quickly eats all his broccoli (which actually tastes pretty good).
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</p>
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<p>
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After dinner, when Timmy asks for his ice cream, he is told no! Does Timmy have a right to be upset? Why or why not?
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</p>
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</blockquote>
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<p>
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Math is about making general claims, but a claim is rarely going to be true of absolutely <em>every</em> mathematical object. The way we <em>restrict</em> our claims to a particular type of object is with an implication: <q>take any object you like, <em>if</em> it is of the right type, <em>then</em> this thing is true about it.</q>
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Math is about making general claims, but a claim is rarely going to be true of absolutely <em>every</em> mathematical object. The way we <em>restrict</em> our claims to a particular type of object is with an implication: <q>Take any object you like, <em>if</em> it is of the right type, <em>then</em> this thing is true about it.</q>
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</p>
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<p>
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Similarly, as we saw in the <xref ref="subsec_logic-statements-quant" text="title"/> subsection, when we make claims like <q>every square is a rectangle,</q> we really have an implication: <q>if something is a square, then it is a rectangle.</q>
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Similarly, as we saw in the <xref ref="subsec_logic-statements-quant" text="title"/> subsection, when we make claims like <q>Every square is a rectangle,</q> we really have an implication: <q>If something is a square, then it is a rectangle.</q>
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</p>
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<p>
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</p>
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<figure xml:id="fig-implication-tt">
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<caption>The truth table for <m>P \imp Q</m></caption>
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<caption>The truth table for <m>P \imp Q</m>.</caption>
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<tabular halign="center">
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<col right="minor"/> <col right="major"/> <col/>
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<row bottom="minor">
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<exercise label="pa-sec-logic-implications-tommy">
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<statement>
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<p>
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Consider the statement <q>If Tommy doesn't eat his broccoli, then he will not get any ice cream.</q> Which of the following statements mean the same thing (i.e., will be true in the same situations)? Select all that apply.
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Consider the statement, <q>If Tommy doesn't eat his broccoli, then he will not get any ice cream.</q> Which of the following statements mean the same thing (i.e., will be true in the same situations)? Select all that apply.
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</p>
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</statement>
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<choices randomize="yes" multiple-correct="yes">
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<exercise label="pa-sec-logic-implications-quant">
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<statement>
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<p>
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Consider the <em>sentence</em>, <q>if <m>x \ge 10</m>, then <m>x^2 \ge 25</m>.</q> This sentence becomes a statement when we replace <m>x</m> by a value, or <q>capture</q> the <m>x</m> in the scope of a quantifier. Which of the following claims are true (select all that apply)?
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Consider the <em>sentence</em>, <q>If <m>x \ge 10</m>, then <m>x^2 \ge 25</m>.</q> This sentence becomes a statement when we replace <m>x</m> by a value, or <q>capture</q> the <m>x</m> in the scope of a quantifier. Which of the following claims are true (select all that apply)?
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</p>
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</statement>
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<choices>
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Then I have not lied; my statement is true.
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However, if Bob did get a 90 on the final and did not pass the class,
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then I lied, making the statement false.
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The tricky case is this: what if Bob did not get a 90 on the final?
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The tricky case is this: What if Bob did not get a 90 on the final?
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Maybe he passes the class, maybe he doesn't.
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Did I lie in either case?
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I think not.
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<example>
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<statement>
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<p>
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Consider the statement, <q>all squares are rectangles,</q> which can also be phrased as, <q>for all shapes, if the shape is a square, then it is a rectangle.</q> Is this statement true or false? Are we sure? What about the following three shapes?
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Consider the statement, <q>All squares are rectangles,</q> which can also be phrased as, <q>For all shapes, if the shape is a square, then it is a rectangle.</q> Is this statement true or false? Are we sure? What about the following three shapes?
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</p>
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<image width="75%">
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<shortdescription>three shapes, a square, a non-square rectangle, and a triangle.</shortdescription>
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</p>
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<p>
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Is the implication true of the rectangle in the middle? Well, that shape is not a square (<m>P</m> is false) and it is a rectangle (<m>Q</m> is true). But look, we believe that all squares are rectangles, so the statement must be true. Even of a rectangle. The only way this works is if <q>true implies false</q> is true!
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Is the implication true of the rectangle in the middle? Well, that shape is not a square (<m>P</m> is false), and it is a rectangle (<m>Q</m> is true). But look, we believe that all squares are rectangles, so the statement must be true. Even of a rectangle. The only way this works is if <q>true implies false</q> is true!
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</p>
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<p>
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Similarly, all squares are rectangles is a true statement, even when we look at a triangle. <m>P</m> is false (the triangle is not a square) and <m>Q</m> is false (the triangle is not a rectangle). Thankfully, we defined implications to be true in this case as well.
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Similarly, all squares are rectangles is a true statement, even when we look at a triangle. <m>P</m> is false (the triangle is not a square), and <m>Q</m> is false (the triangle is not a rectangle). Thankfully, we defined implications to be true in this case as well.
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</p>
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<p>
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We have given shapes that illustrate lines 1, 3, and 4 of the truth table for implications (<xref ref="fig-implication-tt"/>). What shape illustrates line 2? That would need to be a shape that was a square and was not a rectangle... Of course we can't find one, precisely because the statement is true!
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We have given shapes that illustrate lines 1, 3, and 4 of the truth table for implications (<xref ref="fig-implication-tt"/>). What shape illustrates line 2? That would need to be a shape that was a square and was not a rectangle.... Of course we can't find one, precisely because the statement is true!
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</p>
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</solution>
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</example>
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<note>
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<p>
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It is unlikely that we would encounter a statement of the form <m>\exists x (P(x) \imp Q(x))</m>, since this would be automatically true if there was any <m>x</m> that made <m>P(x)</m> false. But if we did, the same rules would apply to the converse, contrapositive, and inverse as above: just ignore the quantifier when swapping and/or negating the parts of the implication.
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It is unlikely that we would encounter a statement of the form <m>\exists x (P(x) \imp Q(x))</m>, since this would be automatically true if there was any <m>x</m> that made <m>P(x)</m> false. But if we did, the same rules would apply to the converse, contrapositive, and inverse as above: Just ignore the quantifier when swapping and/or negating the parts of the implication.
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</p>
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<p>
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For example, <q>for all shapes, if the shape is a square, then it is a rectangle</q> (i.e., all squares are rectangles) has the converse, <q>for all shapes, if the shape is a rectangle, then it is a square</q> (so all rectangles are squares).
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For example, <q>For all shapes, if the shape is a square, then it is a rectangle</q> (i.e., all squares are rectangles) has the converse, <q>For all shapes, if the shape is a rectangle, then it is a square</q> (so all rectangles are squares).
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</p>
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<p>
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The contrapositive of <q>for all shapes, if it is a square, then it is a rectangle</q> is <q>for all shapes, if the shape is not a rectangle, then it is not a square.</q> This is true. In fact, <alert>the contrapositive of a true statement is always true</alert>!
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The contrapositive of <q>For all shapes, if it is a square, then it is a rectangle</q> is <q>For all shapes, if the shape is not a rectangle, then it is not a square.</q> This is true. In fact, <alert>the contrapositive of a true statement is always true</alert>!
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</p>
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<p>
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What would happen if Sue did not get an A but <em>did</em>
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get a 93% on the final?
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Then <m>P</m> would be true and <m>Q</m> would be false.
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Then <m>P</m> would be true, and <m>Q</m> would be false.
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This makes the implication <m>P \imp Q</m> false!
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It must be that Sue did not get a 93% on the final.
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Notice we now have the implication
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(the <q>if</q> part)
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<em>false</em>?
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When I am in the shower but not singing.
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That is the same condition for being false as the statement
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<q>if I'm in the shower,
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That is the same condition for being false as the statement,
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<q>If I'm in the shower,
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then I sing.</q> So the <q>if</q> part is <m>Q \imp P</m>.
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On the other hand, to say,
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<q>I sing only if I'm in the shower</q>
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is equivalent to saying <q>if I sing,
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is equivalent to saying <q>If I sing,
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then I'm in the shower,</q> so the
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<q>only if</q> part is <m>P \imp Q</m>.
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</p>
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It is not especially important to know which part is the
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<q>if</q> or <q>only if</q> part,
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but this does illustrate something very, very important:
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<em>there are many ways to state an implication!</em>
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<em>There are many ways to state an implication!</em>
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</p>
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<example>
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<statement>
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<p>
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Rephrase the implication,
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<q>if I dream, then I am asleep</q>
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<q>If I dream, then I am asleep</q>
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in as many ways as possible.
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Then do the same for the converse.
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</p>

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